Vertically Projected Body

Equations of motion for an object projected vertically upward:
     If an object is projected vertically upwards then its velocity decreases. Here the object motion is against the gravity of earth, so g is taken as -ve. So the object moves vertically upward one dimension only then equations of motions will be
                          
The equation for the distance covered  in nth second Hnth = u-g÷2(2n-1)

Maximum height reached by an object vertically upward:
An object is projected vertically upward direction with initial velocity 'u' and it's reached height 'h' at final velocity 'v'= 0.
       Then applying below velocity-displacement equation 
                        
Maximum height

Once observe that above equation maximum height directly proportional  to initial velocity of an object.

Time of ascent(ta):
The time taken by body projected vertically upwards  to reach maximum height is called its time of ascent. Let time of ascent represents ta.
                   v= u-gt
                   0= u-gta
                   ta= u÷g.                                                         Once observe above equation time of ascent is directly proportional to initial velocity of the body.

Time of descent(td):
The time taken by a freely falling body to touch the ground is called the time of descent. Applying Displacement-Time equation
                        
Time of sescent

Time of flight:
 The total time taken by a body is projected at projection point vertically upward to reach maximum height and the body reaches downward at projection point is called "total time of flight".
       Time of flight = Time of ascent + Time of.                                                                         descent
                      T         = ta+ td
                       T        =u÷g+u÷g
                         T    = 2u÷g

Problems and Solutions 
1)A ball is projected vertically upwards with a velocity  5metre per second. Find the maximum height reached by the body? (Take g is equal to 10 metre second power-2 )

2)A ball is thrown vertically upwards with a velocity u and its reaches maximum height h is time taken 2 seconds. Find initial velocity of the body and maximum height of the body?( g is equal to 10 metre second power -2 )

3)A ball is thrown vertically upwards with velocity u. How much time taken by the ball reaches maximum height h is equal to 30 metres? (Take g is equal to 10 metre second power-2 )

4)A ball is thrown upwards and its reaches a maximum height of 100 metres. Its initial speed is? (Take g is equal to second power-2 )
                    
1)A stone is thrown vertically upwards with a velocity of 10 metre per second. The total time for which the body will remain in the air is?(Taken g is equal to 10 metre second power-2)

2)A body is thrown vertically upward with an initial velocity of 20 metre per second. Find the time of ascent? (Take g is equal to 10 metre second power-2)

3) A body is falling freely from some height, its final velocity is 40 metre per second. Find the time of Descent? (g is equal to 10 metre per second power-2)

4) A body projected vertically upwards and its reaches maximum height. Find  initial velocity of the body? (Time fine time of ascent is equal 4 seconds and take g is equal to 10 metre per second power-2 ) 
                 

PRACTICE QUESTIONS FOR STUDENT'S 

1)A body thrown vertically upwards with initial velocity of 72 kilometre per hour. Find the time of ascent? (Taken g is equal to 10 metre second power -2 )

2)A body is thrown vertically upwards with initial velocity of 10 metre per second. Find maximum height of the body?(Taken g is is equal to 10 metre second power- 2 )

3)A stone is projected vertically upwards with initial velocity u and its reaches maximum height height of 100 metre. Find  time of ascent of the body? (Taken g is equal to 10 metre second power- 2 )

4)A stone is projected vertically upwards with initial velocity 40 metre per second. Find  time of descent of the body?( Taken g is equal to 10 metre second power- 2 )


If you like this concept,  please follow this blog and share to your friends. 
    Thank you .....



Comments

Post a Comment

Popular posts from this blog

Kinematics problems and solutions

Image
1) Given that v=10+3t, (in S.I.Units) using this equation find acceleration ? 2)Given that s=ut+1÷2(at2), (S.I.Units) using this equation find initial velocity? 3)A car moving with a speed of 20m/s can be stopped by applying brakes, after travelling a distance of 10m. The negative Acceleration of the car? 4) A bus travelling with velocity of 54 kmph is brought to rest by applying brakes. It experiences a uniform retardation of 5m/s2. Before coming to rest, how much distance travelled by the bus? 5) A man initially at rest starts moving with a uniform acceleration 'a'. The ratio of the distances covered by it in the first second  and the first four seconds is ? You see this solutions in below video.  1) If a car having an initial velocity 4 m/s,  moves with a uniform acceleration of 2 metre per second square, then the final velocity when it covers a distance of 5 metres is ?                          2)A bus s...
Read more

How to understand physics

Image
Everyone read physics concepts ,but few members don't  understand and few members understand very easily. What is difference between this two category members?                 Let's  i explain about these two category members. Few members are not observe surroundings scientifically, they are only see normally means one tree leafs move to and fro. They are observed, leafs are moving that only. Few members are understand very easily, because they are see surroundings scientifically, that means one tree leafs move to and fro. They are do so many questions themselves,  why are leaves  moving ? They will get idea due to air. What is air? again. Air is a mass.what is mass ? Mass is the amount  of matter contained in a body. What is matter? Matter is a substance occupies  some space.What is a substance? So many questions asks themselves. They will easily understand this type of analysis members.     So, observ...
Read more